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A long straight wire in the horizontal plane carries a current of $50 \mathrm{~A}$ in north to south direction. Give the magnitude and direction of $B$ at a point $2.5 \mathrm{~m}$ east of the wire.
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Given, $\mathrm{I}=50 \mathrm{~A}, \mathrm{a}=2.5 \mathrm{~m}, \mathrm{~B}=$ ?
$$
\mathrm{B}=\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{a}}=\frac{4 \pi \times 10^{-7} \times 50}{2 \pi \times 2.5}=4 \times 10^{-6} \mathrm{~T} \text {. }
$$
It will be in vertically upward direction (right hand thumb rule)
$$
\mathrm{B}=\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{a}}=\frac{4 \pi \times 10^{-7} \times 50}{2 \pi \times 2.5}=4 \times 10^{-6} \mathrm{~T} \text {. }
$$
It will be in vertically upward direction (right hand thumb rule)
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