A loop ABCD has current I = 10 A , as shown in the figure. AD and BC are circular arcs with centre at O , for both. The magnetic field at point O is

Question

A loop ABCD has current I = 10 A , as shown in the figure. AD and BC are circular arcs with centre at O , for both. The magnetic field at point O is, 10 - 4 T, 10 - 5 T, 1.5 × 10 - 5 T, 2 × 10 - 5 T

MARKS App · Accepted Answer

Magnetic field due to AB and CD are zero at O Magnetic field due to BC B B C = μ 0 4 π 10 3 × 10 - 2 × π 4 (outwards) Simplifying field due to DA B S P = μ 0 4 π 10 5 × 10 - 2 × π 4 (inwards) Net field B = μ o 4 π 10 π 4 × 10 - 2 1 3 - 1 5 = 1 .0 × 10 - 5 T

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