A loop ABCD is moving with velocity v towards the right. The magnetic field is 2 T . Loop is connected to a resistance of 9 Ω . If the steady current of 2 A flows in the loop, then the value of v , if loop has resistance of 4 Ω , is (Given AD = 30 cm )

Question

A loop ABCD is moving with velocity v towards the right. The magnetic field is 2 T . Loop is connected to a resistance of 9 Ω . If the steady current of 2 A flows in the loop, then the value of v , if loop has resistance of 4 Ω , is (Given AD = 30 cm ), 86 . 7 m s - 1, 30 m s - 1, 33 . 33 m s - 1, 20 m s - 1

MARKS App · Accepted Answer

When a straight conductor moves with velocity v perpendicular to the magnetic field then emf induced is given by V = B v l . Here, it will be V = B v ( l sin θ ) . Potential difference is V = B v ( l sin θ ) V = 2 × v × 3 0 1 0 0 × 1 2 = 0 · 3 v Now, Current = V R ⇒ 2 = 0 · 3 V 13 ⇒ v = 86 .7 m s - 1

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