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A loop carrying current $\mathrm{I}$ has the shape of a regular polygon of $\mathrm{n}$ sides. If $\mathrm{R}$ is the distance from the centre to any vertex, then the magnitude of the magnetic induction vector $\vec{B}$ at the centre of the loop is -
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The correct answer is:
$\mathrm{n} \frac{\mu_{0} \mathrm{I}}{2 \pi \mathrm{R}} \tan \frac{\pi}{\mathrm{n}}$

$\begin{aligned} \mathrm{B}_{\text {net }} &=\mathrm{n} \times \mathrm{B}_{1} \\ &=\mathrm{n} \cdot \frac{\mu_{0}}{4 \pi} \cdot \frac{\mathrm{I}}{\mathrm{R} \cos \frac{\pi}{\mathrm{n}}} 2 \sin \frac{\pi}{\mathrm{n}} \end{aligned}$
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