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A magnetic dipole is under the influence of two magnetic fields. The angle between the field directions is $60^{\circ}$, and one of the fields has a magnitude of $1.2 \times 10^{-2} \mathrm{~T}$. If the dipole comes to stable equilibrium at an angle of $15^{\circ}$ with this field, what is the magnitude of the other field?
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The magnetic dipole experience torque due to both the fields and is in equilibrium
$N B_1 \sin 15^{\circ}=M B_2 \sin 45^{\circ}$
$1.2 \times 10^{-2} \times 0.26=B_2(0.71)$ or $B_2=0.44 \times 10^{-2} \mathrm{~T}$
$N B_1 \sin 15^{\circ}=M B_2 \sin 45^{\circ}$
$1.2 \times 10^{-2} \times 0.26=B_2(0.71)$ or $B_2=0.44 \times 10^{-2} \mathrm{~T}$
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