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A magnetic field B is confined to a region r a ≤ and points out of the paper (the z-axis), r = 0 being the centre of the circular region. A charged ring (charge = Q) of radius b, b > a and mass m lies in the x-y plane with its centre at the origin. The ring is free to rotate and is at rest. The magnetic field is brought to zero in time ∆t. Find the angular velocity ω of the ring after the field vanishes.
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The correct answer is:
$\omega =\frac{QB{{a}^{2}}}{2m{{b}^{2}}}$
Correct Option is : (B)
$\omega =\frac{QB{{a}^{2}}}{2m{{b}^{2}}}$
$\omega =\frac{QB{{a}^{2}}}{2m{{b}^{2}}}$
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