A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22 0 with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0 .35 G . Determine the magnitude of the earth's magnetic field at the place. cos 22 ° = 0.9272

Question

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22 0 with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0 .35 G . Determine the magnitude of the earth's magnetic field at the place. cos 22 ° = 0.9272, 0 .38 G, 0. 35 G, 0. 3 0 G, 0. 4 0 G

MARKS App · Accepted Answer

Given, angle of dip δ = 2 2 o Horizontal component of the earth's magnetic field H = 0 .35 G Let the magnitude of the earth's magnetic field at the place is R . Using the formula, H = R cos δ or R = H cos δ = 0 . 3 5 cos 2 2 o = 0 . 3 5 0 . 9 2 7 2 = 0 . 3 8 G Thus, the value of the earth's magnetic field at that place is 0 .38 G .

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