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A man applying force of 20 N on an object at an angle of $60^{\circ}$ from the horizontal. If object moved by 20 m in horizontal direction, then work done by the force on the object is
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The correct answer is:
200 J
Given, force, $\mathrm{f}=20 \mathrm{~N}$,
angle
$\theta=60^{\circ}$
and displacement $(\mathrm{s})=20 \mathrm{~m}$,
$\therefore$ Work done by the force
$\begin{aligned}
\mathrm{W} & =\mathrm{fs} \cos \theta=20 \times 20 \times \cos 60^{\circ}=20 \times 20 \times \frac{1}{2} \\
& =200 \mathrm{~J}
\end{aligned}$
angle
$\theta=60^{\circ}$
and displacement $(\mathrm{s})=20 \mathrm{~m}$,
$\therefore$ Work done by the force
$\begin{aligned}
\mathrm{W} & =\mathrm{fs} \cos \theta=20 \times 20 \times \cos 60^{\circ}=20 \times 20 \times \frac{1}{2} \\
& =200 \mathrm{~J}
\end{aligned}$
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