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A man fires a bullet of mass $200 \mathrm{~g}$ at a speed of $5 \mathrm{~m} / \mathrm{s}$. The gun is of one $\mathrm{kg}$ mass. by what velocity the gun rebounds backwards
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The correct answer is:
$1 \mathrm{~m} / \mathrm{s}$
$v_G=\frac{m_B v_B}{m_G}=\frac{0.2 \times 5}{1}=1 \mathrm{~m} / \mathrm{s}$
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