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A man is riding on a cycle with velocity $7.2 \mathrm{kn} / \mathrm{hr}$ up a hill having a slope 1 in 20 . The total mass of the man and cycle is $100 \mathrm{~kg}$. The power of the man is
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98 W
$v=7.2 \frac{\mathrm{km}}{\mathrm{h}}=7.2 \times \frac{5}{18}=2 \mathrm{~m} / \mathrm{s}$
Slope is given 1 in 20
$\therefore \quad \sin \theta=\frac{1}{20}$
When man and cycle moves up then component of weight opposes it motion is
$F=m g \sin \theta$
So power of the man $P=F \times v=m g \sin \theta \times v$
$=100 \times 9.8 \times\left(\frac{1}{20}\right) \times 2=98$ Watt
Slope is given 1 in 20
$\therefore \quad \sin \theta=\frac{1}{20}$
When man and cycle moves up then component of weight opposes it motion is
$F=m g \sin \theta$
So power of the man $P=F \times v=m g \sin \theta \times v$
$=100 \times 9.8 \times\left(\frac{1}{20}\right) \times 2=98$ Watt
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