A man measures the period of a simple pendulum inside a stationary lift and finds it be T . If the lift accelerates downwards with an acceleration of g 3 , then the period of the pendulum will be

Question

A man measures the period of a simple pendulum inside a stationary lift and finds it be T . If the lift accelerates downwards with an acceleration of g 3 , then the period of the pendulum will be, 2 3 T, 3 2 T, T 3, T 3

MARKS App · Accepted Answer

When the lift is moving in a downward direction with an acceleration g 3 then g e f f = g - g 3 = 2 3 g Since we know, the time period of a simple pendulum, T 1 = 2 π l g e f f = 2 π ⋅ l 2 3 g T 1 = 3 2 ⋅ 2 π l g Hence, T 1 = 3 2 T ∵ T = 2 π l g

Search any question & find its solution

Looking for more such questions to practice?