A man of mass 80 k g is riding on a small cart of mass 40 k g which is rolling along a level floor at a speed of 2 m s - 1 . He is running on the cart so that his velocity relative to the cart is 3 m s - 1 in the direction opposite to the motion of the cart. What is the speed of the centre of mass of the system

Question

A man of mass 80 k g is riding on a small cart of mass 40 k g which is rolling along a level floor at a speed of 2 m s - 1 . He is running on the cart so that his velocity relative to the cart is 3 m s - 1 in the direction opposite to the motion of the cart. What is the speed of the centre of mass of the system, 1.5 m s - 1, 1 m s - 1, 3 m s - 1, zero

MARKS App · Accepted Answer

v → c a r t = v → c = 2 i ^ ⇒ v → m = v → m c + v → c ⇒ v → m = - 3 i ^ + 2 i ^ ⇒ v → m = i ^ Now v → c m = 80 - i ^ + 40 2 i ^ 80 + 40 v → c m = 0

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