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Question: Answered & Verified by Expert
A man $P$ has 7 friends, 4 of them are ladies and 3 are men, His wife $Q$ also has 7 friends, 3 of them are ladies and 4 are men. Assume $P$ and $Q$ have no common friends. Then the total number of ways in which $P$ and $Q$ together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of $P$ and $Q$ are in this party, is
MathematicsPermutation CombinationMHT CETMHT CET 2022 (11 Aug Shift 1)
Options:
  • A 468
  • B 485
  • C 484
  • D 469
Solution:
2145 Upvotes Verified Answer
The correct answer is: 485

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