A man stands on a weighing machine kept inside a lift. Initially, the lift is ascending with the acceleration a due to which the reading is W . Now the lift descends with the same acceleration and reading is 10 % of initial. Find the acceleration of lift.

Question

A man stands on a weighing machine kept inside a lift. Initially, the lift is ascending with the acceleration a due to which the reading is W . Now the lift descends with the same acceleration and reading is 10 % of initial. Find the acceleration of lift., g 19, 9 g 11, zero, g

MARKS App · Accepted Answer

N = m g + a N ′ = m g - a N ′ = 10 100 × N m g - a = m g + a 10 10 g - 10 a = g + a 9 g = 11 a ⇒ a = 9 g 11

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