A man throws a packet from a tower directly aiming at his friend who is standing at a certain distance from the base which is same as the height of the tower. If the packet is thrown with a speed of 4 m s - 1 and it hits the ground midway between the tower base & his friend than the height of the tower is g = 10 m s - 2

Question

A man throws a packet from a tower directly aiming at his friend who is standing at a certain distance from the base which is same as the height of the tower. If the packet is thrown with a speed of 4 m s - 1 and it hits the ground midway between the tower base & his friend than the height of the tower is g = 10 m s - 2, 5 m, 8 m, 3.2 m, 13 m

MARKS App · Accepted Answer

4 2 . t = h 2 … . . ( i ) & h = 4 2 t + 1 2 g t 2 … . . ( i i ) From (i) and (ii) h 2 = 1 2 g 4 2 2 ⇒ h 2 = 1 2 g h 4 2 2 h = 16 × 2 10 = 3.2 m

Search any question & find its solution

Looking for more such questions to practice?