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A man weighs $80 \mathrm{~kg}$. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 \mathrm{~m} / \mathrm{s}^2$. What would be the reading on the scale? $\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)$
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Verified Answer
The correct answer is:
$1200 \mathrm{~N}$
Reading of weighing scale
$$
\begin{aligned}
& =m(g+a) \\
& =80(10+5)=1200 \mathrm{~N}
\end{aligned}
$$
$$
\begin{aligned}
& =m(g+a) \\
& =80(10+5)=1200 \mathrm{~N}
\end{aligned}
$$
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