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Question: Answered & Verified by Expert
A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends. Then the total number of ways in which X and Y together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of X and Y are in this party is:
MathematicsPermutation CombinationJEE MainJEE Main 2017 (02 Apr)
Options:
  • A 485
  • B 468
  • C 469
  • D 484
Solution:
1430 Upvotes Verified Answer
The correct answer is: 485
Here, m - men and L - ladies



Total=9×16+1+9×36+16

=144+1+324+16

=485

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