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Question: Answered & Verified by Expert
A marble block of mass 2 kg lying on ice when given a velocity of 6 m s-1 is stopped by friction in 10 s . Then the coefficient of friction is
PhysicsLaws of MotionNEET
Options:
  • A 0.02
  • B 0.03
  • C 0.06
  • D  0.01
Solution:
2644 Upvotes Verified Answer
The correct answer is: 0.06
Let coefficient of friction be μ, and then retardation will be μ g .

From equation of motion, v=u+at

⇒  0=6-μ g×10

⇒  μ=6100=0.06

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