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Question: Answered & Verified by Expert

a marble block of mass 2 kg lying on the ice when given a velocity of  6 m s1 is stopped by frictional force in 10 s. Then the coefficient of friction is 
(take g=10 m s-2)

PhysicsLaws of MotionNEET
Options:
  • A 0.01
  • B 0.02
  • C 0.03
  • D 0.06
Solution:
1647 Upvotes Verified Answer
The correct answer is: 0.06

     v=u+at

      v=uμgt                             ( since   μmg=ma )

      0=6μ×10×10

or  100μ=6

or  μ=6100=0.06

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