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Question: Answered & Verified by Expert
A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to the mass of 3m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is
PhysicsLaws of MotionNEET
Options:
  • A 14vi^+32v j^
  • B 13vi^+23v j^
  • C 23vi^+13v j^
  • D 32vi^+14v j^
Solution:
2915 Upvotes Verified Answer
The correct answer is: 14vi^+32v j^
As the two masses stick together after collision, hence it is inelastic collision. Therefore, only momentum is conserved.



mvi^+3m2vj^=4m v

v=v4i^+64vj^=v4i^+32vj^

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