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A mass ' $M$ ' moving with velocity ' $\mathrm{V}$ ' along $\mathrm{x}$-axis collides and sticks to another mass $2 \mathrm{M}$ which is moving along $\mathrm{Y}$-axis with velocity ' $3 \mathrm{~V}$ '. The velocity of the combination after collision is
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Verified Answer
The correct answer is:
$\frac{V}{3} \hat{i}+2 V \hat{j}$
From law of conservation of linear momentum,
$\begin{aligned}
& M v \hat{i}+2 M(3 v \hat{j})=3 M \vec{v} \\
& v \hat{i}+6 v \hat{j}=3 \vec{v} \\
& \vec{v}=\frac{v}{3} \hat{i}+2 v \hat{j}
\end{aligned}$
$\begin{aligned}
& M v \hat{i}+2 M(3 v \hat{j})=3 M \vec{v} \\
& v \hat{i}+6 v \hat{j}=3 \vec{v} \\
& \vec{v}=\frac{v}{3} \hat{i}+2 v \hat{j}
\end{aligned}$
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