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Question: Answered & Verified by Expert
A mass \( \mathrm{m} \) is suspended from a massless pulley, which it self is suspended by a massless string and a spring as shown in figure. The force constant of spring is \( \mathrm{K} \). What will be the time period of oscillation of \( \mathrm{m} \) :
PhysicsOscillationsJEE Main
Options:
  • A \( 2 \pi \sqrt{\frac{m}{2 K}} \)
  • B \( 2 \pi \sqrt{\frac{m}{K}} \)
  • C \( \pi \sqrt{\frac{m}{K}} \)
  • D \( \pi \sqrt{\frac{m}{2 K}} \)
Solution:
2796 Upvotes Verified Answer
The correct answer is: \( \pi \sqrt{\frac{m}{K}} \)

F=4 K x=ma

T=2πm4K=πmK.

 

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