A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 ° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is g = 10 m s - 2

Question

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 ° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is g = 10 m s - 2, 100 N, 200 N, 140 N, 70 N

MARKS App · Accepted Answer

T cos ⁡ 45 ° = m g T sin ⁡ 45 ° = F t a n 45 ° = F m g F = m g = 100 N

Search any question & find its solution

Looking for more such questions to practice?