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A mass of $2 \mathrm{~kg}$ is suspended with thread $A B$ (figure). Thread $C D$ of the same type is attached to the other end of $2 \mathrm{~kg}$ mass. Lower thread is pulled gradually, harder and harder in the downward direction, so as to apply force on $A B$. Which of the threads will break and why?
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The thread $A B$ will break earlier than the thread $C D$. Because, force acting on thread $C D$ is equal to applied force and the force acting on thread $A B$ is equal to the (applied force + weight of $2 \mathrm{~kg}$ mass).
So, force acting on thread $A B$ is more than the force acting on thread $C D$. Hence, the thread $A B$ will break-up.
So, force acting on thread $A B$ is more than the force acting on thread $C D$. Hence, the thread $A B$ will break-up.
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