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Question: Answered & Verified by Expert
A massless rod BD of length l is suspended by two identical massless strings AB and CD of equal lengths. A block of mass m is suspended from a point P such that BP is equal to x. If the fundamental frequency of the left wire is twice the fundamental frequency of the right wire, then the value of lx is

PhysicsWaves and SoundJEE Main
Solution:
1522 Upvotes Verified Answer
The correct answer is: 5

          f v T

         f AB = 2 f CD

     T AB = 4 T CD                  ...(i)

Further  Σ τ p = 0

T AB x = T CD - x

or  4 x = l - x                                  T AB = 4 T CD

or     x = l / 5

 lx=5

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