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Question: Answered & Verified by Expert
A massless rod of length l is hung from the ceiling with the help of two identical wires attached at its ends. A block is hung on the case, the frequency of the 1st harmonic of the wire on the left end is equal to the frequency of the 2nd harmonic of the wire on the right. The value of X is


PhysicsWaves and SoundJEE Main
Options:
  • A l2
  • B l3
  • C l4
  • D l5
Solution:
2130 Upvotes Verified Answer
The correct answer is: l5
v=λf




T1μT2μ=2lflf

T1T2=4

T1+T2=Mg ; T2=Mg5

ΣtB=0Mg×X=Mg5×l ;

X=l5

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