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Question: Answered & Verified by Expert
A material of \( 0.25 \mathrm{~cm}^{2} \) cross-sectional area is placed in a magnetic field of strength (H) \( 1000 \mathrm{~A} \mathrm{~m}^{-1} \). Then the magnetic flux produced is (Susceptibility of material is \( 313 \) ) (Permeability of free space, \( \mu_{0}=4 \pi \times 10^{-7} \mathrm{H} \mathrm{m}^{-1} \) )
PhysicsMagnetic Properties of MatterJEE Main
Options:
  • A \( 8.33 \times 10^{-8} \) weber
  • B \( 1.84 \times 10^{-6} \) weber
  • C \( 9.87 \times 10^{-6} \) weber
  • D \( 3.16 \times 10^{-6} \) weber
Solution:
1209 Upvotes Verified Answer
The correct answer is: \( 9.87 \times 10^{-6} \) weber
B=μH
μr=1+χ
ϕA=μr . μ0H
1+313=314=100π
ϕ=Aμr . μ0H
μ=μr . μ0, π2=10 9.87
=0.25×10-4×314×4π×10-7×1000
=25×10-6×100π×4π×10-4
=25×4×10-6+2+π2×10-4
=100×10×10-8=10-5
10×10-6 wb

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