Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A merry-go-round is at rest, pivoted on a frictionless axis. A child of mass m runs along the path tangential to the rim with speed v and jumps on to merry-go-round. If R is the radius of the merry-go-round and I is the moment of inertia, then the angular velocity of the merry-go-round and the child is
PhysicsRotational MotionJEE Main
Options:
  • A mvR m R 2 +I
  • B mvR I
  • C m R 2 +I mvR
  • D I mvR
Solution:
1352 Upvotes Verified Answer
The correct answer is: mvR m R 2 +I
By law of conservation of angular momentum

mvR=Isystemω

mvR=I+mR2ω

ω=mvRI+mR2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.