A metal M forms the sulphate M 2 S O 4 3 . A 0.596 gram sample of the sulphate reacts with excess B a C l 2 to give 1.220 g B a S O 4 . What is the atomic weight of M (in g/mol)?

Question

A metal M forms the sulphate M 2 S O 4 3 . A 0.596 gram sample of the sulphate reacts with excess B a C l 2 to give 1.220 g B a S O 4 . What is the atomic weight of M (in g/mol)?, 26.9, 69.7, 55.8, 23

MARKS App · Accepted Answer

Mole of B a S O 4 = 1.22 233.3 Moles of M 2 S O 4 3 = 1.22 233.3 × 1 3 = 1.743 × 10 - 3 Wt. of M 2 S O 4 3 = 0.596 ∴ 1.743 × 10 - 3 2 M + 96 × 3 = 0.596 M = 26.9

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