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A metal $M$ readily forms its sulphate $\mathrm{MSO}_4$ which is water-soluble. It forms its oxide $M O$ which becomes inert on heating. It forms its insoluble hydroxide $\mathrm{M}(\mathrm{OH})_2$ which is soluble in $\mathrm{NaOH}$ solution. Then $M$ is
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$\mathrm{Be}$
The solubility of hydroxides of alkaline earth metals in water increases on moving down the group.
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