A metal oxide has the formula X 2 O 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal in amu is

Question

A metal oxide has the formula X 2 O 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal in amu is, 15.6, 155.8, 30.8, 55.8

MARKS App · Accepted Answer

X 2 O 3 1 m o l ( 2 a + 48 ) + 3 H 2 3 m o l 6 g → 2 X + 3 H 2 O 0.006 g H 2 is required by 0.1596 g oxide So 6 g H 2 will be require by 159.6 g oxide So 2 a + 48 = 159.6 a = 55.8 where, a = atomic mass of metal M.

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