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A metal rod consumes power $P$ on passing current. If it is cut into two half and joined in parallel, it will consume power
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The correct answer is:
$4 P$
Let the resistance of the rod be $R$. If the rod is divided into two equal parts, then each part of the rod will have a resistance of $R / 2$. Now these two parts of the rod are connected in parallel and a voltage $V$ is applied across them. Hence the total power consumed is
$$
P^{\prime}=\frac{V^2}{R / 2}+\frac{V^2}{R / 2}=4 \frac{V^2}{R}=4 P \text { where }
$$
$P=\frac{V^2}{R}$ is the power consumed by the original rod when voltage $V$ is applied across it.
$$
P^{\prime}=\frac{V^2}{R / 2}+\frac{V^2}{R / 2}=4 \frac{V^2}{R}=4 P \text { where }
$$
$P=\frac{V^2}{R}$ is the power consumed by the original rod when voltage $V$ is applied across it.
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