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A metal rod of length $2 m$ is rotating with an angular velocity of 100 $\mathrm{rad} / \mathrm{sec}$ in a plane perpendicular to a uniform magnetic field of $0.3 \mathrm{~T}$. The potential difference between the ends of the rod is
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$60 \mathrm{~V}$
$e=\frac{1}{2} B I^2 \omega=\frac{1}{2} \times 0.3 \times(2)^2 \times 100=60 \mathrm{~V}$
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