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Question: Answered & Verified by Expert
A metal sphere of mass 'm' and density ' $\sigma_{1}$ ' falls with terminal velocity through a
container containing liquid. The density of liquid is ' $\sigma_{2}$ '. The viscous force acting
on the sphere is
PhysicsMechanical Properties of FluidsMHT CETMHT CET 2020 (15 Oct Shift 1)
Options:
  • A $\operatorname{mg}\left(1-\frac{\sigma_{1}}{\sigma_{2}}\right)$
  • B $\operatorname{mg}\left(1-\frac{\sigma_{2}^{\prime}}{\sigma_{1}}\right)$
  • C $\operatorname{mg}\left(1+\frac{\sigma_{1}}{\sigma_{2}}\right)$
  • D $\operatorname{mg}\left(1+\frac{\sigma_{2}}{\sigma_{1}}\right)$
Solution:
2025 Upvotes Verified Answer
The correct answer is: $\operatorname{mg}\left(1-\frac{\sigma_{2}^{\prime}}{\sigma_{1}}\right)$
$\mathrm{F}=\frac{4}{3} \pi \mathrm{r}^{3}\left(\mathrm{~d}_{1}-\mathrm{d}_{2}\right) \mathrm{g}$
$\mathrm{F}=\frac{4}{3} \pi \mathrm{r}^{3} \mathrm{~d}_{1}\left(1-\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right) \mathrm{g}=\mathrm{M}\left(1-\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right) \mathrm{g}$

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