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A metal wire is of length $l$ has magnetic moment $M$. What is the new magnetic moment if it is bent in L-shape?
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Verified Answer
The correct answer is:
$\frac{M}{\sqrt{2}}$
Magnetic wire of length $l$ has magnetic moment $M$, therefore
$M=m l$
where, $\mathrm{m}$ is the strength of each monopole.
If it is bent into $l$ shape the effective separation between the monopoles changes to $\frac{l}{\sqrt{2}}$.
Therefore, new magnetic moment is:
$M^{\prime}=m\left(\frac{l}{\sqrt{2}}\right)=\frac{M}{\sqrt{2}}$
$M=m l$
where, $\mathrm{m}$ is the strength of each monopole.
If it is bent into $l$ shape the effective separation between the monopoles changes to $\frac{l}{\sqrt{2}}$.
Therefore, new magnetic moment is:
$M^{\prime}=m\left(\frac{l}{\sqrt{2}}\right)=\frac{M}{\sqrt{2}}$
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