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A metallic bar is heated from $0^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$. The coeficient of linear expansion is $10^{-5} \mathrm{~K}^{-1}$. What will be the percentage increase in length?
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The correct answer is:
$0.1 \%$
$\begin{aligned}
\frac{\Delta \ell}{\ell}=\alpha \Delta \mathrm{T} &=10^{-5} \times 100=10^{-3} \\
\frac{\Delta \ell}{\ell} \times 100 \% &=10^{-3} \times 100 \\
&=10^{-1}=0.1 \%
\end{aligned}$
\frac{\Delta \ell}{\ell}=\alpha \Delta \mathrm{T} &=10^{-5} \times 100=10^{-3} \\
\frac{\Delta \ell}{\ell} \times 100 \% &=10^{-3} \times 100 \\
&=10^{-1}=0.1 \%
\end{aligned}$
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