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A microscope was initially placed in air (refractive index ). It is then immersed in oil (refractive index ). For a light whose wavelength in air is $\lambda$, calculate the change of microscope's resolving power due to oil and choose the correct option
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The correct answer is:
Resolving power will be twice in the oil than it was in the air.
Resolving power of microscope in air is
Thus, resolving power in oil is twice the resolving power in air.
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