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Question:
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A milliammeter of resistance $40 \Omega$ has a range $0-30 \mathrm{~mA}$. What will be the resistance
used in series to convert it into voltmeter of range $0-15 \mathrm{~V}$ ?
Options:
used in series to convert it into voltmeter of range $0-15 \mathrm{~V}$ ?
Solution:
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Verified Answer
The correct answer is:
$460 \Omega$
(A)
$\begin{aligned} R &=\frac{V}{I_{g}}-G=\frac{15}{30 \times 10^{-3}}-40 \\ &=500-40=460 \Omega \end{aligned}$
$\begin{aligned} R &=\frac{V}{I_{g}}-G=\frac{15}{30 \times 10^{-3}}-40 \\ &=500-40=460 \Omega \end{aligned}$
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