A mixture of 1.0 mole of Al and 3.0 mole of Cl 2 are alloved to react as: 2 Al ( s ) + 3 Cl 2 ( g ) → 2 AlCl 3 ( g ) . Then moles of excess reagent left unreacted is:

Question

A mixture of 1.0 mole of Al and 3.0 mole of Cl 2 are alloved to react as: 2 Al ( s ) + 3 Cl 2 ( g ) → 2 AlCl 3 ( g ) . Then moles of excess reagent left unreacted is:, 3.5, 1.0, 1.5, 2.5

MARKS App · Accepted Answer

2 Al + 3 Cl 2 → 2 AlCl 3 s Moles before reaction 1 .0 3 .0 0 Moles after reaction 0 1 .5 1 .0 Mole ratio for reactants and products are 2 : 3 : 2 Thus limiting reagent is A l . Moles of A l C l 3 formed = 1.0 Moles of excess reagent C l 2 left unreacted = 1.5

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