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Question: Answered & Verified by Expert
A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is:
[Use atomic masses (in g mol1): N=14,Ar=40]
ChemistryStates of MatterNEETNEET 2020 (Phase 1)
Options:
  • A 12 bar
  • B 15 bar
  • C 18 bar
  • D 9 bar
Solution:
2938 Upvotes Verified Answer
The correct answer is: 15 bar

Mass of N2 = 7 g

Moles of N2=728=14

Mass of Ar=8 g

Moles of Ar=840=15

Partial pressureN2=PT×mole fractionN2

=27×1/41/4+1/5

=27×1/49/20

=27×204×9

=3×5

=15 bar

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