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A molecule $(X)$ has (i) four sigma bonds formed by the overlap of $s p^2$ and $s$ orbitals (ii) one sigma bond formed by $s p^2$ and $s p^2$ orbitals and (iii) one $\pi$ bond formed by $p_x$ and $p_z$ orbitals. Which of the following is $X$ ?
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The correct answer is:
$\mathrm{C}_2 \mathrm{H}_4$
Structure of $\mathrm{C}_2 \mathrm{H}_4$ is :
So, the compound $(X)$ is $\mathrm{C}_2 \mathrm{H}_4$.
So, the compound $(X)$ is $\mathrm{C}_2 \mathrm{H}_4$.
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