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Question: Answered & Verified by Expert
A monochromatic beam of light has a frequency v=32π×1012 Hz and is propagating along the direction i^+j^ 2 . It is polarized along the k^ direction. The acceptance form the magnetic field is:
PhysicsElectromagnetic WavesJEE MainJEE Main 2018 (15 Apr)
Options:
  • A E0Ci^+j^ 2 Cos104i^+j^2.r -3×1012t
  • B E0C k^ Cos104i^+j^2.r+3×1012t
  • C  E0Ci^-j^2 Cos104i^+j^2.r+3×1012t
  • D  E0Ci^+j^+k^3Cos104i^+j^2.r+3×1012t
Solution:
1665 Upvotes Verified Answer
The correct answer is:  E0Ci^-j^2 Cos104i^+j^2.r+3×1012t
E^×B^ should have given direction of wave propagation,  K^×B^ i^+j^ 2 
 K^×i^+j^ 2=j^--i^2=i^+j^ 2 i^+j^ 2  

Wave propagation vector K^ should be along i^+j^ 2.

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