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A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation.
If the refractive index of the material of the prism is $\sqrt{3}$,
then the angle of incidence is :
Options:
If the refractive index of the material of the prism is $\sqrt{3}$,
then the angle of incidence is :
Solution:
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Verified Answer
The correct answer is:
$60^{\circ}$
For minimum deviation:
$\mathrm{r}_{1}=\mathrm{r}_{2}=\frac{\mathrm{A}}{2}=30^{\circ}$
by Snell's law $\mu_{1} \sin \mathrm{i}=\mu_{2} \sin \mathrm{r}$
$1 \times \sin i=\sqrt{3} \times \frac{1}{2}=\frac{\sqrt{3}}{2} \Rightarrow i=60$
$\mathrm{r}_{1}=\mathrm{r}_{2}=\frac{\mathrm{A}}{2}=30^{\circ}$
by Snell's law $\mu_{1} \sin \mathrm{i}=\mu_{2} \sin \mathrm{r}$
$1 \times \sin i=\sqrt{3} \times \frac{1}{2}=\frac{\sqrt{3}}{2} \Rightarrow i=60$
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