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A motor cycle is going on an overbridge of radius $R$. The driver maintains a constant speed. As the motor cycle is ascending on the overbridge, the normal force on it
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The correct answer is:
increases
Reaction of normal force on the motor cyclist
$M g \cos \theta-N=\frac{m v^2}{R}$
or $\quad N=M g \cos \theta-\frac{M v^2}{R}$
As the motor cyclist moves upward on the bridge, $\theta$ decreases and therefore, $N$ increases and becomes maximum at the highest point.
$M g \cos \theta-N=\frac{m v^2}{R}$
or $\quad N=M g \cos \theta-\frac{M v^2}{R}$
As the motor cyclist moves upward on the bridge, $\theta$ decreases and therefore, $N$ increases and becomes maximum at the highest point.
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