Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A moving coil galvanometer allows a full scale current of 10-4 A . A series resistance of 2 ×104 Ω is required to convert the galvanometer into a voltmeter of range 0-5 V . Therefore, the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is:
PhysicsCurrent ElectricityJEE MainJEE Main 2019 (10 Apr Shift 1)
Options:
  • A 100 Ω
  • B 200 Ω
  • C 300 Ω
  • D 10 Ω
Solution:
1549 Upvotes Verified Answer
The correct answer is: 300 Ω

ig=10-4 A

 i=10×10-3 A

 RV=20kΩ

igG+igRV=5

igG=i-igRA
RA=igGi-ig=ig5-igRVi-igig
RA=5-igRVi-ig300 Ω

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.