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Question: Answered & Verified by Expert
A narrow but tall cabin is falling freely near the earth's surface. Inside the cabin, two small stones $A$ and $B$ are released from rest (relative to the cabin). Initially $A$ is much above the centre of mass and $B$ much below the centre of mass of the cabin. A close observation of the motion of $A$ and $B$ will reveal that -
PhysicsCenter of Mass Momentum and CollisionKVPYKVPY 2011 (SB/SX)
Options:
  • A both $A$ and $B$ continue to be exactly at rest relative to the cabin
  • B A moves slowly upward and $B$ moves slowly downward relative to the cabin
  • C both $A$ and $B$ fall to the bottom of the cabin with constant acceleration due to gravity
  • D $A$ and $B$ move slightly towards each other vertically
Solution:
2967 Upvotes Verified Answer
The correct answer is: A moves slowly upward and $B$ moves slowly downward relative to the cabin


$a_{B}>a_{C}>a_{A}$
$a_{B}=g$
$\vec{a}_{\Lambda / C M}=\vec{a}_{\Lambda}-\vec{a}_{C M}(\uparrow)$
$\vec{a}_{B / C M}=\vec{a}_{B}-\vec{a}_{C M}(\downarrow)$

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