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A negligibly small current is passed through a wire of length $15 \mathrm{~m}$ and uniform cross-section $6.0 \times 10^{-7}$ $\mathrm{m}^2$, and its resistance is measured to be $5.0 \Omega$. What is the resistivity of the material?
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Given, $l=15 \mathrm{~m}, \mathrm{~A}=6.0 \times 10^{-7} \mathrm{~m}^2, \mathrm{R}=5 \Omega, \rho=?$
By relation, $\mathrm{R}=\rho \frac{\ell}{\mathrm{A}}$
or, $\rho=\frac{\text { RA }}{\ell}=\frac{5 \times 6.0 \times 10^{-7}}{15}=2 \times 10^{-7}$ ohm-m.
By relation, $\mathrm{R}=\rho \frac{\ell}{\mathrm{A}}$
or, $\rho=\frac{\text { RA }}{\ell}=\frac{5 \times 6.0 \times 10^{-7}}{15}=2 \times 10^{-7}$ ohm-m.
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