Search any question & find its solution
Question:
Answered & Verified by Expert
A neon-dioxygen mixture contains $64 \mathrm{~g} \mathrm{O}_2$ and $160 \mathrm{~g} \mathrm{Ne}$. If the total pressure is $25 \mathrm{bar}$, calculate the partial pressure of dioxygen.
Options:
Solution:
2217 Upvotes
Verified Answer
The correct answer is:
5 bar
$\begin{aligned} & \mathrm{n}_{\mathrm{O}_2}=\frac{64}{32}=2 \mathrm{~mol} ; \mathrm{n}_{\mathrm{N}_{\mathrm{e}}}=\frac{160}{20}=8 \mathrm{~mol} \\ & x_{\mathrm{O}_2}=\frac{\mathrm{n}_{\mathrm{O}_2}}{\mathrm{n}_{\text {Total }}}=\frac{2}{2+8}=\frac{2}{10}=0.2 \\ & \mathrm{P}_{\mathrm{O}_2}=x_{\mathrm{O}_2} \times \mathrm{P}_{\text {Total }}=0.2 \times 25=5 \mathrm{bar}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.