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Question: Answered & Verified by Expert
A non–conducting ring of radius R having uniformly distributed charge Q starts rotating about xx' axis passing through diameter with an angular acceleration α, as shown in the figure. Another small conducting ring having radius a aR is kept fixed at the centre of the bigger ring is such a way that axis xx' is passing through its centre and perpendicular to its plane. If the resistance of the small ring is r=1 Ω, find the induced current in it in ampere.
(Given q=16×102μ0 C, R=1 m, a = 0.1 m, α=8 rad s-2)

PhysicsElectromagnetic InductionJEE Main
Solution:
1986 Upvotes Verified Answer
The correct answer is: 8


dq=q2πR.Rdθ=q2π.dθ
di=dqT=qdθω2π2π
di=qω4π2.dθ
dB=μ0di(Rsinθ)22R3
dB=0πμ0sin2θ2Rqω4π2dθ
B=μ0qω16πR
ϕ=Bπa2
ϕ=πa2.μ0qω16πR
ϕ=μ0qωa216R
|ε|=dϕdt
|ε|=μ0qa216Rα .
=8 volt
i=81=8 A.

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