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Question: Answered & Verified by Expert
A non-conducting thin disc of radius R rotates about its axis with an angular velocity w. The surface charge density on the disc varies with the distance r from the center as σr=σ01+rRβ, where σ0 and β are constants. If the magnetic induction at the center is B=910μ0σ0wR, the value of β is
PhysicsMagnetic Effects of CurrentTS EAMCETTS EAMCET 2018 (04 May Shift 1)
Options:
  • A 14
  • B 4
  • C 12
  • D 2
Solution:
2005 Upvotes Verified Answer
The correct answer is: 14

Consider a thin ring of thickness dr at r from the centre of the disc.

  dB=μ0×dI2r

but dI=dQT=dQ2π×ω=σ×2πrdr2π×ω=σωrdr

B=0Rμ02r×σωrdr=0Rωμ02r×σ01+rRβrdr

  B=ωμ0σ020R01+rRβdr=ωμ0σ022+β1+βR

Given B=910μ0σ0wR

  ωμ0σ022+β1+βR=910μ0σ0wR

   5β+10=9β+9β=14

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